√3sinB=2(sinB/2)^2
√3sinB=1-cosB
√3/2sinB+1/2cosB=1/2
sin(B+π/6)=1/2
B+π/6=5π/6
B=2π/3
又sinB=4cosAsinC
sin(A+C))=4cosAsinC
sinAcosC=3cosAsinC
acosC=3ccosA
a*[(a^2+b^2-c^2)/2ab]=3c*[(b^2+c^2-a^2)/2bc
a^2+b^2-c^2=3(b^2+c^2-a^2)
2b^2+4c^2-4a^2=0
1/2*(b/a)^2+(c/a)^2-1=0........(1)
因b^2=a^2+c^2+ac
(b/a)^2=(c/a)^2+(c/a)+1.........(2)
解(1)(2)得
3(c/a)^2+(c/a)-1=0
c/a=(√13-1)/6或c/a=-(√13+1)/6(舍去)
c/a=(√13-1)/6
16题?