已知a+b=35,ab=-3,求下列代数式的值,(1)(a-5)(b-5)(2)?4a2b(a?b)?12ab2(a+13b)

2025-03-30 20:21:55
推荐回答(1个)
回答1:

(1)原式=ab-5(a+b)+25,
=?3?5×

3
5
+25,
=19;
(2)原式=-4a3b+4a2b2-12a2b2-4ab3
=-4a3b-8a2b2-4ab3
=-4ab(a+b)2
=?4(?3)×
9
25

=
108
25