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为什么用dft能进行连续时间信号的频谱分析

2025-04-02 05:34:39

推荐回答（1个）

回答1：

n=[0:1:99];x=2*sin(4*pi*0.01*n)+5*cos(8*pi*0.01*n);n1=[0:1:44];y1=x(1:1:45);Y1=dft(y1,45);magY1=abs(Y1);k1=0:1:44;w1=2*pi/45*k1;subplot(2,2,1);plot(w1/pi,mag(Y1));title('SampleofDTFTMagnitude');n2=[0:1:59];y2=x(1:1:60

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