Ka=6.2×10^-10CN-的电离常数Kh=Kw/Ka=10^-14/6.2×10^-10=1.613x10^-5CN-+H2O=HCN+OH-0.0001-x........x......xKh=cHCN*cOH-/cCN-=x^2/0.0001-x=1.613x10^-5x=0.001，PH=11
