通信达公式添加KDJ金叉请老师们帮忙

2024-11-19 14:24:35
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回答1:

ETWEEN(C>O,CROSS(MA(C,5)/1.015,O),CROSS(MA(C,5)/1.05,O)) AND C/REF(C,1)>1.03 AND CROSS("RSI.RSI1","RSI.RSI3")AND CROSS("KDJ.J","KDJ.K)");

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