若x<-1,则函数f(x)=2-x-(x+1分之1)的最小值为

2024-11-30 15:37:05
推荐回答(2个)
回答1:


回答2:

f(x)=2-x-1/(x+1)
f'(x) = -1 + 1/(x+1)^2
f'(x) =0
(x+1)^2 -1=0
x+1 = 1 or -1
x=0(rej) or -2
f''(x)=-2/(x+1)^3 >0 (min)
min f(x) = f(-2) = 2+2 -1/(-2+1) = 5