甲基丙烯酸缩水甘油酯合成为什么不用丙烯酰氯

2025-02-22 19:53:44
推荐回答(1个)
回答1:

基于碳阴离氧阴离阴离 聚合进行聚合物设计机粒接枝改性力手段本论文阴离聚合基础,研究聚苯乙烯聚环氧化物两类单体合并通环氧 乙烷阴离环聚合,进行二氧化硅表面接枝改性研究具体工作: 1.p-乙烯基苯磺酰氯(SSC)封端剂,进行聚苯乙烯单体合研究 首先,用阴离聚合合性聚苯乙烯,再用封端剂SSC直接封端性聚合物链、1,1-二苯基乙烯(DPE)减封端、及环氧乙烷(EO)减 封端三种合单体,产物~1H NMR结显示用EO减封端才能末端带乙烯基双键目标单体(PS-SS);凝胶渗透色谱(GPC)测试结显示单体具 较窄量布,存微弱肩峰现象,论文研究产应于肩峰量聚苯乙烯二聚体能机理通优化实验案,降低聚苯乙烯二聚体产 几率,终双键含量91%,二聚体含量0.9%单体 其,进步证明SSC合单体程反应性,同与面步封端合形照,我采用两步酯化合单体:首先用酸化 甲醇终止经EO减末端氧阴离性聚苯乙烯链,端羟基化聚苯乙烯(PS-OH),再三乙胺酸吸收剂,与SSC进行酯化反应,同合 目标单体(PS-SS)~1H NMRFT-IR析结显示产物与步封端合单体具完全相同结构,GPC结表明产物没聚苯乙烯二聚体存用种 较宽松条件双键含量97%单体 2.环氧化物单体合研究 首先用引发剂封端两种研究末端(甲基)丙烯酰氧基聚环氧乙烷单体(PEO-MA)合引发剂,甲基丙烯酸羟乙酯 (HEMA)丙烯酸羟基环酯(HCMA)起始剂,经萘钾转化醇钾,引发EO聚合,~1H NMR结显示产物含双键,其能原酯基发强烈水解副反应封端,甲醇起始剂进行PEO聚合,用甲基丙烯酰氯(MAC)封 端PEO性链进行单体合,~1H NMR结证明结构明确目标单体,且具较窄量布,双键含量高达73%论文讨论三异丁基铝单体合实验影 响 其,进行聚环氧乙烷/聚环氧丙烷两嵌段单体(PEO-PPO-MA)合甲醇起始剂,经萘钾转化醇钾,引发EO聚合,再加入第二单体 PO,加入封端剂MAC产物~1HNMR结显示结构明确两嵌段单体,GPC结显示产物具较窄量布,产物双键含量 达73% ,初步研究PEO-PPO-MA作聚合型乳化剂进行苯乙烯乳液聚合应用效,并研究乳化剂佳加料式 3.TDI修饰二氧化硅改性研究 首先用甲苯二异氰酸酯(TDI)化表面带量硅羟基二氧化硅反应,表面带异氰酸酯基团(-NCO)二氧化硅修饰物(SiO_2- TDI)再别用乙二醇缩水甘油与SiO_2-TDI表面-NCO基团反应,表面带烷羟基SiO_2-TDI-EG表面带环氧基团 SiO_2-TDI-PO三种制备PEO接枝改性二氧化硅:(1)SiO_2-TDI-EG起始剂,经萘钾转化醇钾,引发EO聚 合,接枝PEO改性二氧化硅SiO_2-TDI-EG-PEO;(2)SiO_2-TDI-PO作单体,与EO阴离环共聚,同 接枝PEO改性二氧化硅SiO_2-TDI-PO-PEO;(3)通性PEO聚合物链与SiO_2-TDI-PO表面环氧基团反应,用 graft onto制备PEO接枝改性二氧化硅,作与前两种graft from比较固体~(13)C NMR及FT-IR结证实各步反应产物,并用热失重析产物PEO接枝率总机物接枝率 4.二氧化硅表面直接接枝PEO研究 二氧化硅表面硅羟基起始剂,经萘钾转化硅醇钾,三异丁基铝催化作用,引发EO环聚合,直接二氧化硅表面实现PEO接枝改性通固 体~(13)C~(29)Si NMR及FT-IR析证明二氧化硅表面PEO存,并用TG结计算改性产物PEO接枝率论文讨论三异丁基铝作催化剂参与接枝聚合 反应能机理,并通改变实验条件,讨论三异丁基铝用量、所用溶剂及EO加入量二氧化硅改性产物PEO接枝率影响
感觉这样的提问没有什么意义
建议,可以自己查阅下资料

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