用隐函数的方法求

2024-11-02 17:28:21
推荐回答(3个)
回答1:

回答2:

y=e^t -->y^2=e^2t

x=e^-2t =y^-2 =1/y^2
xy^2=1
两边对x求导得
y^2+2xyy'=0
y'=-y/2x
两边对x求导得
y''=-1/2 *(y/x)'

=-1/2 * (y'-1)/x^2
=(1-y')/2x^2
=(1+y/2x)/2x^2
=(2x+y)/4x^3

回答3: