帮忙解几道物理题

2025-01-07 06:40:57
推荐回答(4个)
回答1:

(1)0.5N
因为鸡蛋在咸水中不动,说明鸡蛋所受的合外力为0N,即浮力与重力二力平衡平衡,所以浮力等于重力等于0.5N

(2)10^7N 10^7N 10^3m³
排水量就是排开水的质量,根据浮力公式:
F浮=ρ液gV排,排开的水所受的重力也就是浮力,同时也就是轮船所受的重力。所以满载时,
轮船及货物的重量等于排开的水的重力等于浮力。
为10^7N
m排=1000t=1000000kg
根据m=ρV
所以V=m/ρ=10^3m³

(3)2600000kg 3200000kg
轮船自身质量就是空载时排水量,为2600t,即2600000kg。满载时质量就是轮船自身质量和货物质量和5800000kg,所以货物质量等于满载质量减去自身质量为5800000-2600000=3200000kg

(4)在盐水中,密度大的种子下沉,密度小的上浮,而饱满的种子一定是密度大的,所以会下沉,不饱满的则上浮。

回答2:

0.5N 10^7N 10^7N 10^3N 2600000kg 5800000kg 在体积不变的情况下质量越大密度越大所以密度小的秕谷上浮密度大的实粒下沉.希望能帮到你,手机敲的没写步骤原凉

回答3:

0.5N 10^7N 10^7N 10^3N 2600000kg 2200000kg 在体积不变的情况下质量越大密度越大所以密度小的秕谷上浮密度大的实粒下沉

回答4:

1:0.5N
2:10000000N,10000000N,1000
3:2600T,3200T
4:可以根据密度来分析,因为不饱满的种子的密度小,所以漂浮在水面上(浮力大于重力)。又沉底的种子的密度叫大,故下沉(浮力小于重力)

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