已知m-n=4,mn=-1,求:(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值

已知m-n=4,mn=-1,求:(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.
2024-11-22 16:48:35
推荐回答(1个)
回答1:

(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
=-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=-6mn+3m-3n
=-6mn+3(m-n),
又因为m-n=4,mn=-1,
所以-6mn+3(m-n)=(-6)×(-1)+3×4=6+12=18.