1⼀3+1⼀15+1⼀35+1⼀63+1⼀99 (用裂项法计算)

2024-11-22 23:12:17
推荐回答(1个)
回答1:

1/3=1/1*3=(1/3-1/5)/2,1/15=1/3*5=(1/3-1/5)/2,1/35=1/5*7=(1/5-1/7)/2,1/63=1/7*9=(1/7-1/9)/2,1/99=1/9*11=(1/9-1/11)/2,然后回到原式,
1/3+1/15+1/35+1/63+1/99
=1/1*3+1/3*5+1/5*7+1/7*9+1/9*11
=(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11)/2 中间全部抵消
=(1-1/11)/2
=10/11*1/2
=5/11,